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flimeryrose741 wrote: » first, assume 10=the natural number 10 and 26 = the natural number 26. Divide by it's inverses. 10 / (1/10) + 10 (1/10) = 26/ (1/26) = 200=676 FALSE 10 / (1/10) + 10 (1/10) = 20/ (1/20) = 200 = 400 FALSE
Krayon wrote: » huh? anong magaling? BaB already mentioned this last page, bat sya, walang galing? edit: or the others here?
BigoteAtBalbas wrote: » kasi mas sosyal yung binanggit na "base 13" akin "let" lang
maccie wrote: » magkaiba yung BaB, you forced 10 to be 13... 10(base 13) + 10(base13) = 26 (base 10) or 10(base 16) + 10(base 10) = 26 (base 10)Don't treat 10 as variable because it is a real number *okay*
hypnotized wrote: » 10 is not a real number, it is an integer.
ermonski wrote: » #include <iostream> #include <string> int main() { int x = 13, y = 13, z; z = x + y; cout << "10"; cout << " + "; cout << "10"; cout << " = "; cout << z; return 0; } output:10 + 10 = 26 so yeah, it is possible
pexer26 wrote: » nak ng tokwa! C++ to ah! gawa din ako. import java.io.*; public class TenTen { public static void main (String[] args) throws IOException { String sampleOne = "10 + 10"; if (sampleOne.charAt(sampleOne.length() - 1)) == '0') { System.out.println(sampleOne + " = 26"); } } }
ildiavolo wrote: » easy lang to: 10 (base 16) + 10 (base 10) = 26 (base 10) 0x10 + 10 = 26 16 + 10 = 26
BigoteAtBalbas wrote: » it's ok, 10 base 16 is equal to 16 base 10
BigoteAtBalbas wrote: » no no no 10 base 16 is not A hex = base 16 = 16 bits 0000 0001 0000 0000 = 10
Comments
ano ito?
10 / (1/10) + 10 (1/10) = 10 (10) + 1 = 100 + 1 = 101
yan ang sagot ng formula mo
kasi mas sosyal yung binanggit na "base 13" akin "let" lang
magkaiba yung BaB, you forced 10 to be 13...
10(base 13) + 10(base13) = 26 (base 10) or
10(base 16) + 10(base 10) = 26 (base 10)
Don't treat 10 as variable because it is a real number *okay*
10 is not a real number, it is an integer.
real numbers are integers isn't it? *okay*
Find the Fibonacci numbers whose sum is equal to the given number.
Example:
Given: 89
Sagot: 55 + 21 + 13
ayan bahala na kayo sa buhay nyo
nak ng tokwa! C++ to ah!
gawa din ako.
import java.io.*;
public class TenTen
{
public static void main (String[] args) throws IOException
{
String sampleOne = "10 + 10";
if (sampleOne.charAt(sampleOne.length() - 1)) == '0')
{
System.out.println(sampleOne + " = 26");
}
}
}
1 = real number and an integer.
2 = real number and an integer.
1.2 = a floating point number.
-10 = not a real number but an integer. . . NOT
-10 is not a natural number but an integer. it is a real number at the same time.
because a real number is an integer, a floating point, and a natural number.
in this case, using java is overkill
di ba bawal ang any operation in different base? ...unless of course, you're chuck norris.
A = 10 in Hex
10 = 10 in Dec
A + 10 = 26? in Dec? err... nope
symbol lang nga. pero 10 pa din sya kahit gawin mong base 16.
10 base 16 is not A
hex = base 16 = 16 bits
0000 0001 0000 0000 = 10
what the F?
0000 = 0
0001 = 1
0000 = 0
0000 = 0
then it became 100. no bit can do! ginawa mo namang binary. nalilito na talaga ako.