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# Prove 10 + 10 = 26

• conscious and coherent PEx Influencer ⭐⭐⭐
10.. base 10.. 26.. headache... woaaah ang tatalino ng mga tao dito a or baka hindi ko lang talaga alam yung 10+10=26? first, assume 10=the natural number 10 and 26 = the natural number 26.

Divide by it's inverses.

10 / (1/10) + 10 (1/10) = 26/ (1/26) = 200=676 FALSE

10 / (1/10) + 10 (1/10) = 20/ (1/20) = 200 = 400 FALSE

ano ito?

10 / (1/10) + 10 (1/10) = 10 (10) + 1 = 100 + 1 = 101

yan ang sagot ng formula mo
• Krayon wrote: »
huh? anong magaling? BaB already mentioned this last page, bat sya, walang galing?

edit: or the others here?

kasi mas sosyal yung binanggit na "base 13" akin "let" lang kasi mas sosyal yung binanggit na "base 13" akin "let" lang magkaiba yung BaB, you forced 10 to be 13...

10(base 13) + 10(base13) = 26 (base 10) or

10(base 16) + 10(base 10) = 26 (base 10)

Don't treat 10 as variable because it is a real number *okay*
• conscious and coherent PEx Influencer ⭐⭐⭐
kayo na mathematician... :rotflmao: hahahaha :bop:
• maccie wrote: »
magkaiba yung BaB, you forced 10 to be 13...

10(base 13) + 10(base13) = 26 (base 10) or

10(base 16) + 10(base 10) = 26 (base 10)

Don't treat 10 as variable because it is a real number *okay*

10 is not a real number, it is an integer. hypnotized wrote: »
10 is not a real number, it is an integer. real numbers are integers isn't it? *okay*
• wala pong fraction ang integers
• algorithm na lang

Find the Fibonacci numbers whose sum is equal to the given number.

Example:

Given: 89

Sagot: 55 + 21 + 13

ayan bahala na kayo sa buhay nyo • ermonski wrote: »
#include <iostream>
#include <string>

int main()
{
int x = 13, y = 13, z;
z = x + y;
cout << "10";
cout << " + ";
cout << "10";
cout << " = ";
cout << z;
return 0;
}

output:

10 + 10 = 26

so yeah, it is possible

nak ng tokwa! C++ to ah!

gawa din ako.

import java.io.*;

public class TenTen
{
public static void main (String[] args) throws IOException
{
String sampleOne = "10 + 10";

if (sampleOne.charAt(sampleOne.length() - 1)) == '0')
{
System.out.println(sampleOne + " = 26");
}
}
}
• hypnotized wrote: »
10 is not a real number, it is an integer. 1 = real number and an integer.

2 = real number and an integer.

1.2 = a floating point number.

-10 = not a real number but an integer. . . NOT

-10 is not a natural number but an integer. it is a real number at the same time.

because a real number is an integer, a floating point, and a natural number.
• pexer26 wrote: »
nak ng tokwa! C++ to ah!

gawa din ako.

import java.io.*;

public class TenTen
{
public static void main (String[] args) throws IOException
{
String sampleOne = "10 + 10";

if (sampleOne.charAt(sampleOne.length() - 1)) == '0')
{
System.out.println(sampleOne + " = 26");
}
}
}

in this case, using java is overkill • ildiavolo wrote: »
easy lang to:

10 (base 16) + 10 (base 10) = 26 (base 10)
0x10 + 10 = 26
16 + 10 = 26

di ba bawal ang any operation in different base? ...unless of course, you're chuck norris.

A = 10 in Hex
10 = 10 in Dec

A + 10 = 26? in Dec? err... nope
• it's ok, 10 base 16 is equal to 16 base 10
• pagbigyan mo na uber • it's ok, 10 base 16 is equal to 16 base 10

symbol lang nga. pero 10 pa din sya kahit gawin mong base 16.
• no no no

10 base 16 is not A

hex = base 16 = 16 bits

0000 0001 0000 0000 = 10
• taena nalito na ako nyahaha buset, rusty na
• no no no

10 base 16 is not A

hex = base 16 = 16 bits

0000 0001 0000 0000 = 10

what the F?

0000 = 0
0001 = 1
0000 = 0
0000 = 0

then it became 100. no bit can do! ginawa mo namang binary. nalilito na talaga ako.