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# Prove 10 + 10 = 26

• 10.. base 10.. 26.. headache... woaaah ang tatalino ng mga tao dito a or baka hindi ko lang talaga alam yung 10+10=26? • first, assume 10=the natural number 10 and 26 = the natural number 26.

Divide by it's inverses.

10 / (1/10) + 10 (1/10) = 26/ (1/26) = 200=676 FALSE

10 / (1/10) + 10 (1/10) = 20/ (1/20) = 200 = 400 FALSE

ano ito?

10 / (1/10) + 10 (1/10) = 10 (10) + 1 = 100 + 1 = 101

yan ang sagot ng formula mo
• Krayon wrote: »
huh? anong magaling? BaB already mentioned this last page, bat sya, walang galing?

edit: or the others here?

kasi mas sosyal yung binanggit na "base 13" akin "let" lang • kasi mas sosyal yung binanggit na "base 13" akin "let" lang magkaiba yung BaB, you forced 10 to be 13...

10(base 13) + 10(base13) = 26 (base 10) or

10(base 16) + 10(base 10) = 26 (base 10)

Don't treat 10 as variable because it is a real number *okay*
• kayo na mathematician... :rotflmao: hahahaha :bop:
• maccie wrote: »
magkaiba yung BaB, you forced 10 to be 13...

10(base 13) + 10(base13) = 26 (base 10) or

10(base 16) + 10(base 10) = 26 (base 10)

Don't treat 10 as variable because it is a real number *okay*

10 is not a real number, it is an integer. • hypnotized wrote: »
10 is not a real number, it is an integer. real numbers are integers isn't it? *okay*
• wala pong fraction ang integers
• algorithm na lang

Find the Fibonacci numbers whose sum is equal to the given number.

Example:

Given: 89

Sagot: 55 + 21 + 13

ayan bahala na kayo sa buhay nyo • ermonski wrote: »
#include <iostream>
#include <string>

int main()
{
int x = 13, y = 13, z;
z = x + y;
cout << "10";
cout << " + ";
cout << "10";
cout << " = ";
cout << z;
return 0;
}

output:

10 + 10 = 26

so yeah, it is possible

nak ng tokwa! C++ to ah!

gawa din ako.

import java.io.*;

public class TenTen
{
public static void main (String[] args) throws IOException
{
String sampleOne = "10 + 10";

if (sampleOne.charAt(sampleOne.length() - 1)) == '0')
{
System.out.println(sampleOne + " = 26");
}
}
}
• hypnotized wrote: »
10 is not a real number, it is an integer. 1 = real number and an integer.

2 = real number and an integer.

1.2 = a floating point number.

-10 = not a real number but an integer. . . NOT

-10 is not a natural number but an integer. it is a real number at the same time.

because a real number is an integer, a floating point, and a natural number.
• pexer26 wrote: »
nak ng tokwa! C++ to ah!

gawa din ako.

import java.io.*;

public class TenTen
{
public static void main (String[] args) throws IOException
{
String sampleOne = "10 + 10";

if (sampleOne.charAt(sampleOne.length() - 1)) == '0')
{
System.out.println(sampleOne + " = 26");
}
}
}

in this case, using java is overkill • ildiavolo wrote: »
easy lang to:

10 (base 16) + 10 (base 10) = 26 (base 10)
0x10 + 10 = 26
16 + 10 = 26

di ba bawal ang any operation in different base? ...unless of course, you're chuck norris.

A = 10 in Hex
10 = 10 in Dec

A + 10 = 26? in Dec? err... nope
• it's ok, 10 base 16 is equal to 16 base 10
• pagbigyan mo na uber • it's ok, 10 base 16 is equal to 16 base 10

symbol lang nga. pero 10 pa din sya kahit gawin mong base 16.
• no no no

10 base 16 is not A

hex = base 16 = 16 bits

0000 0001 0000 0000 = 10
• taena nalito na ako nyahaha buset, rusty na
• no no no

10 base 16 is not A

hex = base 16 = 16 bits

0000 0001 0000 0000 = 10

what the F?

0000 = 0
0001 = 1
0000 = 0
0000 = 0

then it became 100. no bit can do! ginawa mo namang binary. nalilito na talaga ako.